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Feb 26, 2011 · I want to get the list of dates in between these two dates. Can anyone help me pointing the mistake in my query. select Date,TotalAllowance from Calculation where EmployeeId=1 and Date between 2011/02/25 and 2011/02/27 Here Date is a datetime variable.
Feb 2, 2012 · You can write a generator function that returns date objects starting from today: import datetime def date_generator(): from_date = datetime.datetime.today() while True: yield from_date from_date = from_date - datetime.timedelta(days=1)
Sep 29, 2008 · However, if the dates are datetime.datetime objects, it is not as straightforward because .days rounds down no matter if the difference is positive or negative. For example, in the following example, the time difference between the two datetimes is 5 hours and if we use timedelta.days to get the number of days, that difference becomes 0 days or -1 day depending on which datetime was subtracted ...
Jul 11, 2010 · You can work around this by first normalizing the two dates to UTC, and then calculating the difference between those two UTC dates. Now, the solution can be written as, const _MS_PER_DAY = 1000 * 60 * 60 * 24; // Discard the time and time-zone information.
Jan 29, 2009 · The easiest way to compare dates in javascript is to first convert it to a Date object and then compare these date-objects. Below you find an object with three functions: dates.compare(a,b) Returns a number:-1 if a < b; 0 if a = b; 1 if a > b; NaN if a or b is an illegal date; dates.inRange (d,start,end) Returns a boolean or NaN:
Nov 12, 2013 · For my queries on MS Access, I can compare dates with this syntax: SELECT COUNT(orderNumber) AS Total FROM Orders WHERE orderDate >=#2003/04/01# AND orderDate <=#2003/06/30#; Where the output is the number of orders between 2003-04-01 and 2003-06-30.
Mar 31, 2015 · To select the rows between 2017-01-01 and 2019-01-01, you need only to convert the date column to an index: df.set_index('date', inplace=True) and then only slicing: df.loc['2017':'2019'] You can select the date column as index while reading the csv file directly instead of the df.set_index():
Jan 20, 2009 · SELECT * FROM Users WHERE RegistrationDate >= '1/20/2009'. it will automatically convert the string '1/20/2009' into the DateTime format for a date of 1/20/2009 00:00:00. So by using >= you should get every user whose registration date is 1/20/2009 or more recent. Edit: I put this in the comment section but I should probably link it here as well.
Sep 29, 2010 · If the field to compare is from type datetime and only dates are specified for comparison, then these dates are internally converted to datetime values. This means that the following query. SELECT * FROM `objects` WHERE (date_time_field BETWEEN '2010-01-30' AND '2010-09-29') will be converted to
Jan 5, 2013 · From_Date or To_Date could be between your date range or the record dates could cover the whole range. If one of From_date or To_date is between the dates, or From_date is less than start date and To_date is greater than the end date; then this row should be returned.
