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17.5 cm². Answer : B. The area of parallelogram is given by, base × height cm². Therefore, the area of the given parallelogram = 10 × 3.5 = 35 cm². Question 2: The hypotenuse of a right-angled isosceles triangle is 5 cm The area of the triangle is: 5 cm². 6.25 cm².
Area of Rhombus= (d1×d2) 2. where d 1 is the diagonal while d 2 is the length of the other diagonal. The formula for finding the perimeter is. P = 4s. where ‘ s ‘ is the length of the side. In summary, the rhombus has all the properties of a parallelogram but all the parallelogram are not the rhombus.
The area of a parallelogram whose adjacent sides are determined by the vectors → a = ˆ i + 2 ˆ j + 3 ˆ k, a n d → b = − 3 ˆ i − 2 ˆ j + ˆ k View Solution Q 5
Area (ABD) – Area (EBD) = Area (ADC) – Area (EDC) If you look at the figure, ABD – EBD = ABE. Also, ADC – EDC = AEC. Hence, Area (ABE) = Area (AEC). Proved. Question-What is the formula of finding an area of the parallelogram? Answer-As we know the opposite sides are equal in length and opposite angles are also equal in measure.
Area of a parallelogram = $$ side \times altitude$$ $$ \Rightarrow a \times h $$ = 60 $$ \Rightarrow a \times 5 $$ = 60 $$ \Rightarrow a= \dfrac{60}{5} $$ $$ \Rightarrow a=12 cm $$ Was this answer helpful?
Find the area of the parallelogram determined by the vectors: (i) 2 i ^ and 3 j ^ (ii) 2 i ^ + j ^ + 3 k ...
The two adjacent sides of a parallelogram are 2 i ^-4 j ^-5 k ^ and 2 i ^ + 2 j ^ + 3 k ^. Find the two unit vectors parallel to its diagonals. Using the diagonal vectors, find the area of the parallelogram.
The two adjacent sides of a parallelogram are 2 i ^-4 j ^-5 k ^ and 2 i ^ + 2 j ^ + 3 k ^. Find the two unit vectors parallel to its diagonals. Using the diagonal vectors, find the area of the parallelogram.
Click here:point_up_2:to get an answer to your question :writing_hand:area of a parallelogram whose diagonals are 3hat ihat j2hat k and hat i3hat j4hat
A parallelogram with the coordinates of its vertices P(6, 10), Q(8, 10), R(3, 7), and S(1, 7) is plotted on the coordinate plane.
