Search results
- Dictionaryfunction/ˈfʌŋ(k)ʃn/
noun
- 1. an activity that is natural to or the purpose of a person or thing: "bridges perform the function of providing access across water" Similar
- 2. a relation or expression involving one or more variables: "the function (bx + c)"
verb
- 1. work or operate in a proper or particular way: "her liver is functioning normally" Similar Opposite
Powered by Oxford Dictionaries
Souler. 11 1 1 3. 2. use := instead of = and read about Set and SetDelayed. – eldo. Oct 18, 2015 at 17:53. 3. Note that if you do not include a space between x and y in xy, the latter will be considered as an independent variable of name xy. This being said, defining f[x_, y_] = (y/x) + x y and asking for f[1, 2] works fine for me and returns 4.
Each function should document any side effects it makes. Things like creating a file, or updating a file, and such are considered a side-effect and can't be prevented by the language. But should be documented in the function header, so someone reading this function later on, can see right away what are its side-effects. $\endgroup$ –
Mar 1, 2015 · 1. This works: f[u_, x_] := D[u, x] + a[x] u. By way of explanation, everything is an expression, and there is nothing particularly special about functions. You and I know that this definition doesn't have lot of meaning for objects "u" that aren't functions, but Mathematica doesn't need to know that u is a function.
Sep 12, 2016 · First argument of f function is first element of sequence, second argument is standard sequence specification, so {n} will give n-th element of sequence, {min, max} will give list containing elements from min to max, max will give elements from 1 to max.
I'd like to define a function by way of the output of a definite integral with symbolic bounds. For instance, F[m_,k_] := Integrate[x,{x,m,k}] would define F[m_,k_] := (1/2)(k^2 - m^2) This seems to work fine for simple examples, but I've run into the cases where the evaluation takes much longer than the indefinite integral. For instance running.
Mar 15, 2018 · I think it's easier just to define this straight up, rather than compute something procedurally. f[1, 0] = 77; f[0, 1] = 66; f[_, _] = 0; Mathematica is fundamentally an expression rewriting system, so telling it how to rewrite expressions directly like this is usually clearer, faster, and easier to debug.
In Matlab, such issue is handled by varargout, // a cell structure to store all output arguments varargin, // a cell structure to store all input arguments nargout, // number of output arguments ...
TrueQ[OptionValue["Quiet"]], Message[AmakeB::Function, fn] ]; ] Now the function that is created is not returned via a Return from the Module but is added to the Global context. One of the advantages to me is that now I can define an arbitrarily complex function. Usage: AmakeB[1, 1] Returns nothing but now the function Fun exists:
Usually, we define a function as . F[x_] := x + 10 where the right-hand side is an expression. Now, I would like define a function where the right-hand side is the solution of a set of equations. Like . optV[V_, r_, λ_, μ_, η_, σ_] := V /.
So again, yes you can define a function that has: any number of arguments, any number of local variables, routines that set local variables, and; return any, all, or any combination of the local variables. Note one can also define local functions inside a function then use them just as you would any other. A simple if kind of silly example follows:
