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1. tardigrade.in › question › displaystyle-lim-x-pi-4-tan-x-tan-2x-equals-1qw7igacdisplaystyle limx → (π/4) (tan x)tan 2x equals - Tardigrade

   tardigrade.in › question › displaystyle-lim-x-pi-4-tan-x-tan-2x-equals-1qw7igac

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   displaystyle limx → (π/4) (tan x)tan 2x equals (A) e1 (B) e2 (C) e-1 (D) e-2. Check Answer and Solution for above question from Mathematics in Lim

2. tardigrade.in › question › let-p-lim-x-0-1-tan-2-x-1-2x-then-log-p-is-equal-toLet p = displaystyle limx → 0+ ( 1 + tan2 √x ) (1/2x) then log p...

   tardigrade.in › question › let-p-lim-x-0-1-tan-2-x-1-2x-then-log-p-is-equal-to

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   JEE Main 2016: Let p = displaystyle limx → 0+ ( 1 + tan2 √x )(1/2x) then log p is equal to (A) 2 (B) 1 (C) (1/2) (D) (1/4).

3. tardigrade.in › question › displaystyle-lim-x-0-a-sin-x-x-b-tan-x-x-where-a-b-aredisplaystyle lim x arrow 0 [ (a sin x/x)]+ [ (b tan x/x)], where...

   tardigrade.in › question › displaystyle-lim-x-0-a-sin-x-x-b-tan-x-x-where-a-b-are

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   displaystyle lim x arrow 0[(a sin x/x)]+[(b tan x/x)], where a, b are integers and [] denotes integral part, is equal to (A) a+b (B) a+b-1 (C) a-b (D

4. tardigrade.in › question › displaystyle-lim-x-0-cos-tan-x-cos-x-x-4-is-equal-todisplaystyle lim x arrow 0 ( cos ( tan x)- cos x/x4) is equal to

   tardigrade.in › question › displaystyle-lim-x-0-cos-tan-x-cos-x-x-4-is-equal-to

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   displaystyle lim x arrow 0 ( cos ( tan x)- cos x/x4) is equal to (A) 1 / 6 (B) -1 / 3 (C) 1 / 2 (D) 1. Check Answer and Solution for above question f

5. tardigrade.in › question › lim-x-1-tan-x-2-1-x-1-is-equal-to-xf3i7obzdisplaystyle limx → 1 ( tan (x2-1)/x-1) is equal to - Tardigrade

   tardigrade.in › question › lim-x-1-tan-x-2-1-x-1-is-equal-to-xf3i7obz

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   KCET 2007: displaystyle limx → 1 ( tan (x2-1)/x-1) is equal to (A) (1/2) (B) 2 (C) (-1/2) (D) -2. Check Answer and Solution for above question from

6. tardigrade.in › question › displaystyle-lim-x-0-tan-x-2x-4-2-is-equal-to-jv0dmrybdisplaystyle limx→0(( tan x/√2x +4 - 2)) is equal to - Tardigrade

   tardigrade.in › question › displaystyle-lim-x-0-tan-x-2x-4-2-is-equal-to-jv0dmryb

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   KCET 2020: displaystyle limx→0(( tan x/√2x +4 - 2)) is equal to (A) 2 (B) 3 (C) 4 (D) 6. Check Answer and Solution for above question from Mathema

7. tardigrade.in › question › the-value-of-displaystyle-lim-x-0-1-x-tan-1-x-1-2x-1-piThe value of displaystyle limx →0 (1/x) [ tan-1 ( (x+1/2x+1))-...

   tardigrade.in › question › the-value-of-displaystyle-lim-x-0-1-x-tan-1-x-1-2x-1-pi

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   The value of displaystyle limx →0 (1/x) [ tan-1 ((x+1/2x+1))- (π/4)] is (A) 1 (B) -(1/2) (C) 2 (D) 0. Check Answer and Solution for above question

8. tardigrade.in › question › lim-n-infinity-summation-n-r-1-tan-1-2r-r-4-r-2-2-jf4wrzhflim n → ∞ ∑ nr=1 Tan-1((2r/r4 + r2 + 2 )) = - Tardigrade

   tardigrade.in › question › lim-n-infinity-summation-n-r-1-tan-1-2r-r-4-r-2-2-jf4wrzhf

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   AP EAMCET 2018: lim n → ∞ ∑ nr=1 Tan-1((2r/r4 + r2 + 2 )) = (A) (π/4) (B) (π/2) (C) ( - π/4) (D) ( - π/2).

9. tardigrade.in › question › if-f-x-displaystyle-lim-n-infinity-tan-pi-x-2-x-1-n-sinif f(x) = displaystyle limn→∞( (tan π x2+(x+1)n sin x ... -...

   tardigrade.in › question › if-f-x-displaystyle-lim-n-infinity-tan-pi-x-2-x-1-n-sin

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   if f(x) = displaystyle limn→∞( (tan π x2+(x+1)n sin x/x2+(x+1)n)), then (A) f is continuous at x = 0 (B) f is differentiable at x = 0 (C) f is co

10. tardigrade.in › question › underset-x-0-mathop-lim-tan-pi-4-x-1-x-is-equal-to-ep1rbmwzundersetx→ 0 mathop lim tan ( (π /4)+x ) 1/x is equal to -...

    tardigrade.in › question › underset-x-0-mathop-lim-tan-pi-4-x-1-x-is-equal-to-ep1rbmwz

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    J K CET 2013: undersetx→ 0 mathop lim tan ( (π /4)+x ) 1/x is equal to (A) e (B) e2 (C) 1/e (D) 1/e2 . Check Answer and Solution for above q