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Nov 30, 2023 · Roy Kerr, and Einstein I presume, apparently does not agree with him. He states. When theory predicts singularities, the theory is wrong! Regarding his argument about equation of state I would like to quote Dennis Lehmkuhl General Relativity as a Hybrid theory: The Genesis of Einstein’s work on the problem of motion
Jan 2, 2020 · Oh, to finish this and show that this is definitely inside the inner horizon, remember that the horizon is located at the location Δ =r2 +a2 − 2Mr = 0 Δ = r 2 + a 2 − 2 M r = 0, which the quadratic equation gives as located at: r = M ± M2 −a2− −−−−−−√ r = M ± M 2 − a 2. which has an inner r value greater than zero ...
Oct 20, 2021 · As you can see, in order for it to diverge in Kerr spacetime, we need both. r = 0 and θ = π 2. r = 0 and θ = π 2. So it is not a three-dimensional spacelike singularity (4 dimensions minus 1 constraint — r = 0 r = 0), as in the Schwarzschild metric, but a two-dimensional one that has a ring-like quality to it, related to θ θ being equal ...
Mar 6, 2016 · Kerr black holes (and Kerr-Newman black holes), instead of the "point" singularity theorized in spherically symmetric black holes, instead have a "ring" singularity, spread along the equatorial plane of rotation. any particle inside a spherically symmetric black hole will tend to go towards the center.
Feb 24, 2024 · Roy Kerr recently wrote a paper critical of the Penrose singularity theorem. One interpretation of his paper is that the singularity problem might be an artifact of the Schwarzchild metric and that a singularity would not be inevitable in a Kerr metric.
May 20, 2024 · Roy Kerr's interest in black holes goes beyond the ringlike singularity which is presented in his mathematical model only as a placeholder for a progenitor physical object like a dead star or collapsed gas cloud.
R. Kerr posted an essay on arxiv recently. Kerr claims: The consensus view for sixty years has been that all black holes have singularities. There is no direct proof of this, only the papers by Pe...
Mar 8, 2017 · Why does Roy Kerr claim that the Kerr black hole does not contain a singularity? In a preprint posted on the arXiv, Roy Kerr claims that there is a widespread misunderstanding related to the singularity inside the black hole that bears his name.
Sep 4, 2024 · In the extreme case of a Kerr black hole which has passed its angular momentum limit, the frame dragging effect becomes so strong that it allows for an observer to get arbitrarily close to the singularity without crossing an event horizon - hence, no event horizon exists. This is problematic of course, so it is conjectured that black holes have ...
Apr 9, 2019 · In the Kerr metric the ring singularity is located at the coordinate radius r = 0 r = 0, which corresponds to a ring with the cartesian radius R = a R = a. So the center of the ring singularity in cartesian coordinates is at r = −a, θ = π/2 r = − a, θ = π / 2. But the center in cartesian coordinates is also at r = 0, θ = 0 r = 0, θ ...
