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Mar 24, 2017 · In a game of Russian Roulette, there are 6 chambers, one of which has a bullet in it. You are playing with one other person. You go first. Now, your chance of getting hit is 1/6. After firing (and not getting hit), you can either pull the trigger again (1/5 probability of getting hit), or you can pass the gun and let Player 2 try.
Jan 5, 2012 · 1. For 2 players and n chambers player 1 loses if the round is in the odd-numbered chamber. Hence if n n is even, chances are 50/50 50 / 50 and if n is odd, chances of losing are (n+1 2n, n−1 2n (n + 1 2 n, n − 1 2 n) - it's a disadvantage to go first. Share.
Aug 15, 2017 · Typical Russian Roulette question, but I can't get my head around it: 1 person has a gun with 1 bullet (6 chambers). He spins the chambers before every attempt. What are the odds that he WON'T survive 4 tries? The solution should be 0.8024, but I have no idea how to get to that result.
Mar 8, 2018 · Thus, the probability distribution P(X = n) can be found considering that: the player having played n turns means that he survided this n turns. This is the same probability as above and hence P(X = n) = pn. The mean value then becomes. X = ∞ ∑ n = 1nP(X = n) = ∞ ∑ n = 0npn = p d dp ∞ ∑ n = 0pn = p d dp 1 1 − p = p 1 (1 − p)2.
Two men plays Russian roulette. In revolver there are 2 bullets in consecutive chambers( 2 bullets are in 2 chambers next to each other). One man spun the cylinder, pulled the trigger and he is fine, so the chamber was empty. What should the second man do: pull the trigger or spin the cylinder. My answer: Pull the trigger. Explanation:
May 26, 2020 · The problem asks whether you should spin again or not spin. The implication being that we want to avoid shooting ourselves and the game will end immediately after the next time the trigger is pulled. If we weren't to spin again, we will shoot ourselves with probability Pr(A ∣ B) = 15 P r (A ∣ B) = 1 5.
Dec 3, 2014 · Egg Russian Roulette: 6 eggs, 5 of which are hard boiled & 1 of which is raw. Players (1v1) each choose eggs in a turn based system whereby the egg is smashed against the forehead. The first player to smash the raw egg against his/her forehead is the loser.
Mar 4, 2017 · OPTION A 1/6 chance of shooting the ceiling and winning followed by a 4/5 chance of aiming at his own head and pulling the trigger with no bullet coming out and surviving his turn to fire. Or. OPTION B 1/6 chance of aiming at his own head and losing with the first pull of the trigger or a 5/6 chance of surviving his turn to fire.
Sep 11, 2023 · Alternative approach is to simply find the probability that the gun did not fire in the first 8 tries, which is q8. Following through on the original poster's approach, the probability that the gun fires for the first time on try k where k ∈ Z ≥ 9, is. qk − 1p. Then, you would want. ∞ ∑ k = 9qk − 1p = q8 × p × (1 + q + q2 + q3 ...
Aug 31, 2015 · 1. Then is there something else fancy going on? Otherwise it's just a ratio of # of chances for a specific event total # of outcomes # of chances for a specific event total # of outcomes. You have two chances to get shot out of six possible events (each chamber is an event). Since it's spun every round, past events don't affect the outcome.
