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  1. Nov 6, 2023 · Answer. Answer: Fisrtly , as it is given that sin A = P/H = 3/4 , now we will take P=3K , H=4K now by Pythagoras theorem B=√7K . Now, we will find other trigonometric ratios i.e. cos A , cosec A , tan A , sec A .

  2. Mar 11, 2024 · If x/3=2 sinA, y/3=2cos A,then the value of x²+y² is . See answers. Advertisement. rk3638270. suchetatamboli3. We're in the know. Company. Careers. Advertise with us.

  3. Jun 28, 2024 · x(cos(p)cos(y) + sin(p)sin(y)) + sin(y)(cos(p) + x*sin(p)) = 0. Factor out sin(y): sin(y)(x(cos(p) + sin(p)) + cos(p)) = 0. This implies that either sin(y) = 0 or the expression inside the parentheses is equal to 0. Since p is a constant, we can differentiate both sides of the equation with respect to x: d/dx (x(cos(p) + sin(p)) + cos(p)) = 0

  4. Jan 21, 2024 · sinA=3/4, find cosA cosecA + tanA secA - 59450581

  5. Jun 30, 2014 · Which is the correct way to write 507,021 in expanded form?(can someone please help me i really neeed help)

  6. Aug 23, 2021 · Three friends - Anshu, Vijay and Vishal are playing hide and seek in a park. Anshu and Vijay hide in the shrubs and Vishal have to find both of them. If - 45628912

  7. Dec 30, 2016 · Click here 👆 to get an answer to your question ️ Solve : sin 7x + sin 4x + sinx = o

  8. Oct 14, 2023 · An alternating voltage is given by v = 75 sin(200πt − 0.25) volts. To find : (a) The amplitude (b) The peak-to-peak value (c) The r.m.s. value (d) The periodic time (e) The frequency (f) The phase angle . Solution : Step 1 of 6: Calculate amplitude . Here the given equation is . v = 75 sin(200πt − 0.25) ∴ Amplitude = 75 V. Step 2 of 6:

  9. Nov 9, 2023 · sin a = 1/√2. a = 45° [by trigonometric ratios] cot b = √3 . b = 30° [by trigonometric ...

  10. Apr 12, 2024 · Find an answer to your question find value of k if sin inverse[k tan (2cos inverse √ 3/2)]=π/3

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